REASONING – INEQUALITY

REASONING INEQUALITY

STAGE V

EITHOR-OR AND

NEITHOR- NOR

CASE I :

K>=B=Q>=M>=T

  • K=T
  • K>T

RULES:-

  • BOTH CONCLUSION MUST BE WRONG
  • BOTH ELEMENTS SHOULD EQUAL

ALL ABOVE RULES COMPELTETLY FOLLOWED

AND RESULT:-K>=T

SO EITHOR I OR II CONCLUSION CAN FOLLOW

I>=N=K>=L=P

  • I=P
  • P>I

APPLYING RULES

STATSFACTORY RESULT :-I>=P

  • SO NEITHOR I NOR II CONCLUSIONFOLLOW

 

CASE II

O>=H>T=Q<=R=B

  • O>B
  • O<=B

RULES:-

  • BOTH CONCLUSION MUST BE WRONG
  • BOTH ELEMENT MUST BE SAME
  • BOTH SHOULD HAVE OPP SIGN
  • AND ALSO THREE SIGN BETWEEN THE ELEMENTS

 

SOLUTION:

ALL RULES SATISFIED AND FOUND THIS CONCLUSION

:- O>Q<=B

  • O>B
  • O<B
  • O=B
  • EITHOR I OR II CONCLUSION FOLLOW

N=Q>L=T<H

  • N>H
  • N<H

SOLUTION:-

ALL RULES SATISFIED AND FOUND THIS CONCLUSION

:-N>T<H

  • N>H
  • N=H
  • N<H
  • NEITHOR I NOR II CONCLUSION FOLLOW

 

CASE III

 

A>=Q=R<H<J

  • A>=M
  • A<M

IN THIS CASE III WE ASSUME A NEW ELEMENT A, AND WILL ASSUME CONCLUSION WITH RESPECTIVE

SOLUTION:-

APPLY ALL RULES

  • A>M
  • A<M
  • A=M
  • EITHOR I OR II CONLCUSION FOLLOW

Q<N=T>=J

  • Q<=R
  • Q<R

 

SOLUTION :

APPLY ALL RULES

FOUND:-

NEITHOR I OR II CONCLUSION FOLLOW

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